12-3x/3x^2-48=0

Solution for 12-3x/3x^2-48=0 equation:

12-3x/3x^2-48=0


Domain of the equation: 3x^2!=0

x^2!=0/3

x^2!=√0

x!=0

x∈R


We add all the numbers together, and all the variables

-3x/3x^2-36=0

We multiply all the terms by the denominator


-3x-36*3x^2=0

Wy multiply elements

-108x^2-3x=0

a = -108; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·(-108)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*-108}=\frac{0}{-216}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*-108}=\frac{6}{-216}
=-1/36
$